4x^2-92x+304=0

Solution for 4x^2-92x+304=0 equation:

4x^2-92x+304=0

a = 4; b = -92; c = +304;
Δ = b2-4ac
Δ = -922-4·4·304
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-60}{2*4}=\frac{32}{8}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+60}{2*4}=\frac{152}{8}
=19
$